document.write( "Question 813298: A farmer mixed gasoline and oil to have 2 gallons of mixture for his chain saw. The mixture was 32 parts gasoline to 1 part oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and 1 part oil? \r
\n" ); document.write( "\n" ); document.write( "My attempt: .32 (2) + 1 (X) = .40 (2 + X)
\n" ); document.write( " .64 + X = .8 + .4X
\n" ); document.write( " X = .2666 gal of gas to be added\r
\n" ); document.write( "\n" ); document.write( " The author says it is .48 gal of gas to be added\r
\n" ); document.write( "\n" ); document.write( "Thanks,\r
\n" ); document.write( "\n" ); document.write( "Bob \r
\n" ); document.write( "\n" ); document.write( "P. S. I am not a student. I am 67 and just trying to keep my brain working.\r
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Algebra.Com's Answer #489571 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "re reply:  Great idea!
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document.write( "Yes, the \"fraction\" 1/33 says the oil is 1/33 of the entire mixture
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document.write( "The 2 gal mixture was 32 parts gasoline to 1 part oil. 
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document.write( "How much gasoline must be added to bring the mixture to 
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document.write( "40 parts gasoline and 1 part oil? 
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document.write( "(32:1 does not say there is 32% gas)
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document.write( "the Oil as a % is easier to work with: 1/33 0r 1/41
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document.write( "As You had let x represent gas added
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document.write( "   |Cross Multiplying to solve
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