document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68730>Question 68730</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to know: How would i convert (x^2+y^2+2x-10=0) into  (x-h)^2+(y-k)^2=r^2  format? I needed to find the radius and the center of the equation.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48957 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> convert (x^2+y^2+2x-10=0) into (x-h)^2+(y-k)^2=r^2 format<BR>\n" );
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document.write( "You need to \"complete the square\" on the x terms and separately<BR>\n" );
document.write( "on the y terms, as follows:\r<BR>\n" );
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document.write( "(x^2+2x+1) + (y^2) = 10+1<BR>\n" );
document.write( "(x+1)^2 + (y-0)^2 = [sqrt(11)]^2<BR>\n" );
document.write( "Center is at (-1,0)<BR>\n" );
document.write( "Radius is sqrt(11)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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