document.write( "Question 68753This question is from textbook
\n" ); document.write( ": I understand the function of a domain when f(x) is given along with the equation, but I do not understand how to find the domain of the function.\r
\n" ); document.write( "\n" ); document.write( "f(x)=1-2x^2
\n" ); document.write( "f(x)=3^sqrt y-10
\n" ); document.write( "f(x)=4^sqrt x+1/x-2
\n" ); document.write( "Thank you for your help!!!!!
\n" ); document.write( "Christopher
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Algebra.Com's Answer #48953 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
I understand the function of a domain when f(x) is given along with the equation, but I do not understand how to find the domain of the function.
\n" ); document.write( "look for critical points of x ..like division by zero, square root of
\n" ); document.write( "negative number etc...which makes the operation in admissible. they
\n" ); document.write( "are to be eliminated from domain .hence domain is all real numbers except
\n" ); document.write( "those critical points.
\n" ); document.write( "f(x)=1-2x^2
\n" ); document.write( "there is no critical point. hence domain is all real values
\n" ); document.write( "f(x)=3^sqrt y-10
\n" ); document.write( "here sqrt(x-10) is involved.hence domain is all real values of x except
\n" ); document.write( "x<10
\n" ); document.write( "f(x)=4^sqrt x+1/x-2
\n" ); document.write( "same way (x+1)/(x+2)should be >=0....x=-1....or.....
\n" ); document.write( "both x+1 and x+2 should be +ve...hence x>-1
\n" ); document.write( "or
\n" ); document.write( "both x+1 and x+2 should be -ve....hence x<-2
\n" ); document.write( "hence domain is
\n" ); document.write( "x=-1,x>-1,x<-2
\n" ); document.write( "x=[-1,infinity)U(-infinity,-2)\r
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\n" ); document.write( "\n" ); document.write( "Thank you for your help!!!!!
\n" ); document.write( "Christopher
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