document.write( "Question 68753This question is from textbook
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document.write( ": I understand the function of a domain when f(x) is given along with the equation, but I do not understand how to find the domain of the function.\r
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document.write( "f(x)=1-2x^2
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document.write( "f(x)=3^sqrt y-10
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document.write( "f(x)=4^sqrt x+1/x-2
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document.write( "Thank you for your help!!!!!
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document.write( "Christopher \n" );
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Algebra.Com's Answer #48953 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! I understand the function of a domain when f(x) is given along with the equation, but I do not understand how to find the domain of the function. \n" ); document.write( "look for critical points of x ..like division by zero, square root of \n" ); document.write( "negative number etc...which makes the operation in admissible. they \n" ); document.write( "are to be eliminated from domain .hence domain is all real numbers except \n" ); document.write( "those critical points. \n" ); document.write( "f(x)=1-2x^2 \n" ); document.write( "there is no critical point. hence domain is all real values \n" ); document.write( "f(x)=3^sqrt y-10 \n" ); document.write( "here sqrt(x-10) is involved.hence domain is all real values of x except \n" ); document.write( "x<10 \n" ); document.write( "f(x)=4^sqrt x+1/x-2 \n" ); document.write( "same way (x+1)/(x+2)should be >=0....x=-1....or..... \n" ); document.write( "both x+1 and x+2 should be +ve...hence x>-1 \n" ); document.write( "or \n" ); document.write( "both x+1 and x+2 should be -ve....hence x<-2 \n" ); document.write( "hence domain is \n" ); document.write( "x=-1,x>-1,x<-2 \n" ); document.write( "x=[-1,infinity)U(-infinity,-2)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thank you for your help!!!!! \n" ); document.write( "Christopher \n" ); document.write( " |