document.write( "Question 813188: Find 3 consecutive positive integers such that the product of the first and the third is 29 more than the second. Please respond!!! Thank you!:) \n" ); document.write( "
Algebra.Com's Answer #489520 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "let \"3\" consecutive positive integers be:
\n" ); document.write( " \"x\"-first,
\n" ); document.write( "\"%28x%2B1%29\"-second,and
\n" ); document.write( "\"%28x%2B2%29\"-third\r
\n" ); document.write( "\n" ); document.write( "if the product of the first and the third is \"29\" more than the second, then we have\r
\n" ); document.write( "\n" ); document.write( " \"x%28x%2B2%29=%28x%2B1%29%2B29\".....solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2x=x%2B1%2B29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2x=x%2B30\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2x-x-30=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx-30=0\".........write \"x\" as \"6x-5x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B6x-5x-30=0\".....group\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B6x%29-%285x%2B30%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%28x%2B6%29-5%28x%2B6%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-5%29%28x%2B6%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"%28x-5%29++=+0\"=>\"x=5\"\r
\n" ); document.write( "\n" ); document.write( "\"+%28x%2B6%29+=+0\"=>\"x=-6\".....since we need consecutive positive integers, disregard this solution\r
\n" ); document.write( "\n" ); document.write( "so, your consecutive positive integers are:
\n" ); document.write( "\"x=5\"
\n" ); document.write( "\"x%2B1=6\"
\n" ); document.write( "\"x%2B2=7\"
\n" ); document.write( " \n" ); document.write( "
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