document.write( "Question 68744: Write the equation of the line with slope -1/2 and y-intercept (0, 3). Then graph the line.\r
\n" ); document.write( "\n" ); document.write( "I need help with this graphing equation. Thanks
\n" ); document.write( "

Algebra.Com's Answer #48949 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Writing the equation in the slope-intercept form \"y+=+mx%2Bb\" will give you:
\n" ); document.write( "\"y+=+%28-1%2F2%29x%2B3\"
\n" ); document.write( "The graph can be produced by finding two points that are solutions to the equation. The simplest way is to first let x = 0 and solve for y to get the coordinates of the first point (the y-intercept) then do the same thing in reverse, let y = 0 and solve for x to get the coordinates of the second point (the x-intercept).
\n" ); document.write( "Let x = 0
\n" ); document.write( "\"y+=+%28-1%2F2%29%280%29%2B3\" Simplify.
\n" ); document.write( "\"y+=+3\"
\n" ); document.write( "The first point is (0, 3)
\n" ); document.write( "Ley y = 0
\n" ); document.write( "\"0+=+%28-1%2F2%29x%2B3\" Simplify. Subtract 3 from both sides.
\n" ); document.write( "\"-3+=+%28-1%2F2%29x\" Multiply both sides by -2.
\n" ); document.write( "\"6+=+x\"
\n" ); document.write( "The second point is (6, 0)
\n" ); document.write( "Now you would plot these two points on your coordinate graph paper after having drawn the x-axis and the y-axis, then connect the two points with a straight line and you're done! It should look like the graph below:
\n" ); document.write( "\"graph%28300%2C200%2C-5%2C8%2C-5%2C5%2C%28-1%2F2%29x%2B3%29\"
\n" ); document.write( "
\n" );