document.write( "Question 812981: I need to make a diluted bleach solution of .005%. Using 250ml of water, how much bleach would I use to bring it to .005% dilution? \n" ); document.write( "

Algebra.Com's Answer #489437 by jsmallt9(3758) $\"\"$ $\"About$

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The percent bleach in the final solution would be:
\n" ); document.write( " $\"p+=+%28b%2F%28250%2Bb%29%29+%2A+100\"$
\n" ); document.write( "where 'p' is the percent, b is the amount of bleach and (250+b) would be the total amount of the diluted solution.

\n" ); document.write( "We can substitute in the given percentage and solve for b:
\n" ); document.write( " $\"0.005+=+b%2F%28250%2Bb%29+%2A+100\"$
\n" ); document.write( "Simplifying:
\n" ); document.write( " $\"0.005+=+100b%2F%28250%2Bb%29\"$
\n" ); document.write( "Multiplying by 205+b (to eliminate the fraction:
\n" ); document.write( " $\"%280.005%29%28250%2Bb%29+=+%28100b%2F%28250%2Bb%29%29%28250%2Bb%29\"$
\n" ); document.write( "Simplifying:
\n" ); document.write( " $\"%280.005%29%28250%2Bb%29+=+%28100b%2F%28250%2Bb%29%29%28250%2Bb%29\"$
\n" ); document.write( " $\"1.25+%2B+0.005b+=+100b\"$
\n" ); document.write( "Subtracting 0.005b:
\n" ); document.write( " $\"1.25++=+99.995b\"$
\n" ); document.write( "Dividing by 99.995:
\n" ); document.write( " $\"1.25%2F99.995++=+99.995b%2F99.995\"$
\n" ); document.write( "Simplifying:
\n" ); document.write( " $\"0.012500625+=+b\"$ (The decimal is a rounded-off approximation.)
\n" ); document.write( "So to get the desired dilution, add approximately 0.012500625 ml of bleach. \n" ); document.write( "

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