document.write( "Question 68738: Complete the ordered pair so that each is a solution for the given equation.\r
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document.write( "3x + 4y = 12 (0, ), ( ,3/4), (,0), (8/3, ) \n" );
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Algebra.Com's Answer #48942 by rmromero(383)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "To complete the ordered pairs, we need to substitute the given coordinate to the equation. \n" ); document.write( "3x + 4y = 12, (x, y) \n" ); document.write( " \n" ); document.write( "When x = 0 \n" ); document.write( "3(0) + 4y = 12 \n" ); document.write( "4y = 12 \n" ); document.write( "y = 3 -------->> (0, 3) \n" ); document.write( " \n" ); document.write( "When y = 3/4 \n" ); document.write( "3x + 4(3/4) = 12 \n" ); document.write( "3x + 3 = 12 \n" ); document.write( "3x = 9 \n" ); document.write( "x = 3 ----->> (3, (3/4)) \n" ); document.write( " \n" ); document.write( "When y = 0 \n" ); document.write( "3x + 4(0) = 12 \n" ); document.write( "3x = 12 \n" ); document.write( "x = 4 ---------> (4, 0) \n" ); document.write( " \n" ); document.write( "When x = 8/3 \n" ); document.write( "3(8/3) + 4y = 12 \n" ); document.write( "8 + 4y = 12 \n" ); document.write( "4y = 4 \n" ); document.write( "y = 1 -------->> ((8/3), 1) \n" ); document.write( " |