document.write( "Question 68738: Complete the ordered pair so that each is a solution for the given equation.\r
\n" ); document.write( "\n" ); document.write( "3x + 4y = 12 (0, ), ( ,3/4), (,0), (8/3, )
\n" ); document.write( "

Algebra.Com's Answer #48942 by rmromero(383)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "To complete the ordered pairs, we need to substitute the given coordinate to the equation.
\n" ); document.write( "3x + 4y = 12, (x, y)
\n" ); document.write( "

\n" ); document.write( "When x = 0
\n" ); document.write( "3(0) + 4y = 12
\n" ); document.write( "4y = 12
\n" ); document.write( "y = 3 -------->> (0, 3)
\n" ); document.write( "

\n" ); document.write( "When y = 3/4
\n" ); document.write( "3x + 4(3/4) = 12
\n" ); document.write( "3x + 3 = 12
\n" ); document.write( "3x = 9
\n" ); document.write( "x = 3 ----->> (3, (3/4))
\n" ); document.write( "

\n" ); document.write( "When y = 0
\n" ); document.write( "3x + 4(0) = 12
\n" ); document.write( "3x = 12
\n" ); document.write( "x = 4 ---------> (4, 0)
\n" ); document.write( "

\n" ); document.write( "When x = 8/3
\n" ); document.write( "3(8/3) + 4y = 12
\n" ); document.write( "8 + 4y = 12
\n" ); document.write( "4y = 4
\n" ); document.write( "y = 1 -------->> ((8/3), 1)
\n" ); document.write( "
\n" );