document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=812685>Question 812685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In an isosceles triangle, the two equal sides each measure 14 meters, and they include an angle of 45 degrees.  Find the area of the isosceles triangle, to the nearest square meter.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #489412 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=489412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In an isosceles triangle, the two equal sides each measure 14 meters, and they include an angle of 45 degrees. Find the area of the isosceles triangle, to the nearest square meter.<BR>\n" );
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document.write( "Formula: Area = a*b*sin(C)<BR>\n" );
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document.write( "Your Problem::<BR>\n" );
document.write( "Area = 14*14*sin(45)<BR>\n" );
document.write( "Area = 14^2*sqrt(2)/2<BR>\n" );
document.write( "Area = 98*sqrt(2) sq meters<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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