document.write( "Question 812911: Log(3)3^5+log(5)125 \n" ); document.write( "

Algebra.Com's Answer #489401 by jsmallt9(3758) $\"\"$ $\"About$

You can put this solution on YOUR website!
Please include the instructions when posting. I can only guess that we are supposed to simplify this expression.

\n" ); document.write( " $\"log%283%2C+%283%5E5%29%29%2Blog%285%2C+%28125%29%29\"$
\n" ); document.write( "Logarithms are exponents. The first log represents the exponent you would put on 3 to get $\"3%5E5\"$ . Clearly this exponent must be a 5. So the first log is equal to 5:
\n" ); document.write( " $\"5+%2B+log%285%2C+%28125%29%29\"$
\n" ); document.write( "The second log represents the exponent you would put on a 5 to get 125. This one is not as obvious. But if you start exploring powers of 5 you will find that $\"125+=+5%5E3\"$ . So the exponent for 5 that results in 125 is 3:
\n" ); document.write( "5 + 3
\n" ); document.write( "which simplifies to:
\n" ); document.write( "8
\n" ); document.write( " \n" ); document.write( "

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