document.write( "Question 812890: The perimeter of a rectangle is 36 inches. If the length is 4 inches longer than the width, how do I find the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #489391 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,\r
\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is 36 inches.
\n" ); document.write( "If the length is 4 inches longer than the width, find the dimensions
\n" ); document.write( "
\n" ); document.write( "Let x represent the width, then (x+4) is the length
\n" ); document.write( "Question states*****
\n" ); document.write( " 36 = 2(x+4) + 2x
\n" ); document.write( "Solving for x
\n" ); document.write( "2x + 8 + 2x = 36
\n" ); document.write( "4x = 28
\n" ); document.write( "x = 7in, the width. The length is 11in (x+4)
\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 22in + 14in = 36in
\n" ); document.write( " \n" ); document.write( "
\n" );