document.write( "Question 812889: The length of a rectangle is 7 yards less than 3 times its width. If the perimeter is 66 yards find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #489385 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "The length of a rectangle is 7 yards less than 3 times its width
\n" ); document.write( "perimeter is 66 yards
\n" ); document.write( "
\n" ); document.write( "Let x represent the width, then length is (3x-7)
\n" ); document.write( "Question states******
\n" ); document.write( " 66yds = 2(3x-7) + 2x
\n" ); document.write( "Solving for x
\n" ); document.write( " 8x = 80
\n" ); document.write( " x = 10yds, the width and the length is 23yds
\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 46 + 20 = 66yds \n" ); document.write( "
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