document.write( "Question 68636This question is from textbook
\n" ); document.write( ": x=-3
\n" ); document.write( "y=2x + 1
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Algebra.Com's Answer #48938 by tutorcecilia(2152)\"\" \"About 
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x=-3
\n" ); document.write( "y=2x + 1
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\n" ); document.write( "Substitute x=-3 into the second equation and solve for y
\n" ); document.write( "y=2(-3)+1
\n" ); document.write( "y=-6+1
\n" ); document.write( "y=-5
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\n" ); document.write( "Plug y=-5 back into the second equation and solve for x:
\n" ); document.write( "-5=2x+1
\n" ); document.write( "-5-1=2x+1-1
\n" ); document.write( "-6=2x
\n" ); document.write( "-3=x [checks out]
\n" ); document.write( "or
\n" ); document.write( "y=2x+1
\n" ); document.write( "(-5)=2(-3)+1
\n" ); document.write( "-5=-6+1
\n" ); document.write( "-5=-5 [also checks out]\r
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