document.write( "Question 812562: The area of a rug is 48 square feet and the width is 2 feet less than the length, find the width of the carpet. I know the answer is 6 feet. BUT HOW DO YOU GET 6??? \n" ); document.write( "
Algebra.Com's Answer #489365 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,\r
\n" ); document.write( "\n" ); document.write( "The area of a rug is 48 square feet and the width is 2 feet less than the length, find the width of the carpet.
\n" ); document.write( "
\n" ); document.write( "Let x represent the length and (x-2) represent the width
\n" ); document.write( "Question states*****
\n" ); document.write( " x(x-2) = 48 ft^2\r
\n" ); document.write( "\n" ); document.write( "Solving for x
\n" ); document.write( "x^2 - 2x - 48 = 0
\n" ); document.write( "(x+6)(x-8) = 0
\n" ); document.write( "(x+6) = 0, x = -6 (throwing out negative solution for unit measure)
\n" ); document.write( "(x-8) = 0 , x = 8', the length and the width is 6' (x-2)
\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( "( 8')(6') = 48 ft^2 \n" ); document.write( "
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