document.write( "Question 812809: the sum of three numbers is 2008
\n" ); document.write( "the second is 2 less than twice
\n" ); document.write( "the first and the third is 9 more than thrice the second.
\n" ); document.write( "find the three numbers.
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Algebra.Com's Answer #489354 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( " sum of three numbers is 2008
\n" ); document.write( "Let x represent the first number
\n" ); document.write( "the second is 2 less than twice the first 0r 2x-2
\n" ); document.write( " the third is 9 more than thrice the second 0r 3(2x-2) + 9\r
\n" ); document.write( "\n" ); document.write( " x + (2x-2) + 3(2x-2)+9 = 2008 ***
\n" ); document.write( " 9x +1 = 2008
\n" ); document.write( " 9x = 2007
\n" ); document.write( " x = 223
\n" ); document.write( "Numbers are 223, 444, 1341\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 223 + 444 + 1341 = 2008 \n" ); document.write( "
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