document.write( "Question 812758: If the perimeter of a rectangle is 96 and the length is 4 inches longer than the width what is the area? \n" ); document.write( "

Algebra.Com's Answer #489338 by KMST(5328) $\"\"$ $\"About$

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$\"w\"$ = the width of the rectangle, in inches
\n" ); document.write( " $\"w%2B4\"$ = the length of the rectangle, in inches
\n" ); document.write( "For a rectangle,
\n" ); document.write( " $\"perimeter=length%2Bwidth%2Blength%2Bwidth\"$ ,
\n" ); document.write( "or $\"perimeter=2length%2B2width\"$
\n" ); document.write( "or $\"perimeter=2%28length%2Bwidth%29\"$ ,
\n" ); document.write( "so we can calculate it many ways.
\n" ); document.write( "I'll pick one, but all ways would lead to the same $\"4w%2B8\"$ expression.
\n" ); document.write( " $\"perimeter=2w%2B2%28w%2B4%29\"$
\n" ); document.write( "My first equation would be
\n" ); document.write( " $\"2w%2B2%28w%2B4%29=96\"$
\n" ); document.write( " $\"2w%2B2w%2B8=96\"$
\n" ); document.write( " $\"4w%2B8=96\"$
\n" ); document.write( " $\"4w%2B8-8=96-8\"$
\n" ); document.write( " $\"4w=88\"$
\n" ); document.write( " $\"4w%2F4=88%2F4\"$
\n" ); document.write( " $\"w=22\"$
\n" ); document.write( "That means that the width is 22 inches, so the length must be 26 inches, because
\n" ); document.write( " $\"w%2B4=22%2B4\"$ --> $\"w%2B4=26\"$
\n" ); document.write( "So, the area must be
\n" ); document.write( " $\"%2822inches%29%2826inches%29=highlight%28572%29\"$ $\"square\"$ $\"inches\"$ . \n" ); document.write( "

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