document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68720>Question 68720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On this problem, my instructor asks that we use the Pythagoreans Theorem.\r<BR>\n" );
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document.write( "The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the<BR>\n" );
document.write( "rectangle?\r<BR>\n" );
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document.write( "I have come up with L = 2.44 cm and W = 1.44 cm. Is this correct??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48932 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I DID NOT COME UP WITH THE SAME ANSWER AS YOU BUT WE ARE FAIRLY CLOSE.  MAYBE YOU CAN CHECK BOTH OUR SOLUTIONS----PTAYLOR\r<BR>\n" );
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document.write( "In a right triangle, the Pythagorean Theorem states<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2=a%5E2%2Bb%5E2%29 ALIGN=MIDDLE  ALT=\"c%5E2=a%5E2%2Bb%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > where c is the hypotenuse and a and b are the respective sides.\r<BR>\n" );
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document.write( "Let x= width of rectangle\r<BR>\n" );
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document.write( "Then x+1=length of rectangle<BR>\n" );
document.write( "We are told that the diagonal or{or hypotenuse of the triangle) is 4 cm.  So or equation to solve is:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B%28x%2B1%29%5E2=%284%5E2%29 ALIGN=MIDDLE  ALT=\"x%5E2%2B%28x%2B1%29%5E2=%284%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  clear parens<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2Bx%5E2%2B2x%2B1=16 ALIGN=MIDDLE  ALT=\"x%5E2%2Bx%5E2%2B2x%2B1=16\"   DISABLED_style= \"max-width:90%; height:auto;\" > subtract 16 from both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2%2B2x-15=0 ALIGN=MIDDLE  ALT=\"2x%5E2%2B2x-15=0\"   DISABLED_style= \"max-width:90%; height:auto;\" > quadratic in standard form\r<BR>\n" );
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document.write( "Using the quadratic formula: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-2+%2B-+sqrt%28+4%2B120+%29%29%2F%284%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-2+%2B-+sqrt%28+4%2B120+%29%29%2F%284%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-2+%2B-+11.135%29%2F%284%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-2+%2B-+11.135%29%2F%284%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28%2B9.135%29%2F%284%29+ ALIGN=MIDDLE  ALT=\"x+=+%28%2B9.135%29%2F%284%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=2.2837+ ALIGN=MIDDLE  ALT=\"x+=2.2837+\"   DISABLED_style= \"max-width:90%; height:auto;\" >cm -----------------------------width<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B1=2.2837%2B1=3.2837 ALIGN=MIDDLE  ALT=\"x%2B1=2.2837%2B1=3.2837\"   DISABLED_style= \"max-width:90%; height:auto;\" >------------------------length\r<BR>\n" );
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document.write( "I think that we can discount the negative value for x\r<BR>\n" );
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document.write( "Hope this helps----ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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