document.write( "Question 812702: During the first part of a trip a bicyclist travels 59 miles at a certain speed the return trip is made at a speed that is 6 mph slower total time for the round trip is 15 hours find the bicyclists average speed on each part of the trip. \n" ); document.write( "

Algebra.Com's Answer #489257 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
For each trip, $\"+d+=+59+\"$ mi
\n" ); document.write( "Let $\"+t+\"$ = the time in hrs for the 1st part of the trip
\n" ); document.write( "Let $\"+s+\"$ = the speed in mi/hr for the 1st part of the trip
\n" ); document.write( "----------------
\n" ); document.write( "Equation for 1st part:
\n" ); document.write( "(1) $\"+59+=+s%2At+\"$
\n" ); document.write( "Equation for 2nd part
\n" ); document.write( "(2) $\"+59+=+%28+s-6+%29%2A%28+15+-+t+%29+\"$
\n" ); document.write( "--------------------------
\n" ); document.write( "(2) $\"+59+=+15s+-+90+-+s%2At+%2B+6t+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+t+=+59%2Fs+\"$
\n" ); document.write( "---------------
\n" ); document.write( "(2) $\"+t%2A%28+s+-+6+%29+=+15s+-+90+-+59+\"$
\n" ); document.write( "(2) $\"+t%28+s-6+%29+=+15s+-+149+\"$
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+%2859%2Fs%29%2A%28+s-6+%29+=+15s+-+149+\"$
\n" ); document.write( "(2) $\"+59%2A%28+s-6+%29+=+15s%5E2+-+149s+\"$
\n" ); document.write( "(2) $\"+59s+-+354+=+15s%5E2+-+149s+\"$
\n" ); document.write( "(2) $\"+15s%5E2+-+208s+%2B+354+=+0+\"$
\n" ); document.write( "You can finish - the kitty has his front leg stretched across
\n" ); document.write( "the keyboard\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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