document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=812668>Question 812668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A passenger train's speed is 60 mi/h, and a freight train's speed is 40 mi/h. The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #489252 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=489252\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Time freight train - time passenger train = 1.5\r<BR>\n" );
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document.write( "let distance =x<BR>\n" );
document.write( "time freight train = x/40<BR>\n" );
document.write( "time passenger train = x/60\r<BR>\n" );
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document.write( "x/40-x/60 =1.5<BR>\n" );
document.write( "multiply by the LCD 120\r<BR>\n" );
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document.write( "3x-2x=1.5*120\r<BR>\n" );
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document.write( "x=180 miles distance\r<BR>\n" );
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document.write( "time taken = 180/60 = 3hours passenger train<BR>\n" );
document.write( "180/40 =4.5 hours - freight train </SPAN>\n" );
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