document.write( "Question 812599: Sprinter A runs 100 meters in 15 seconds, while sprinter B starts 1.5 seconds later and runs 100 meters in 14 seconds. If each of them runs at a constant rate, who is further in 10 seconds after the start of the race? \n" ); document.write( "
Algebra.Com's Answer #489233 by TimothyLamb(4379)\"\" \"About 
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s = d / t
\n" ); document.write( "d = s * t
\n" ); document.write( "---
\n" ); document.write( "a = 100/15 m/sec
\n" ); document.write( "b = 100/14 m/sec
\n" ); document.write( "---
\n" ); document.write( "at 10 seconds:
\n" ); document.write( "a has run a distance of:
\n" ); document.write( "d = (100/15) * 10 = 66.7 meters
\n" ); document.write( "---
\n" ); document.write( "at 10 seconds:
\n" ); document.write( "b has only been running for 8.5 seconds and so has run a distance of:
\n" ); document.write( "d = (100/14) * 8.5 = 60.7 meters
\n" ); document.write( "---
\n" ); document.write( "Answer:
\n" ); document.write( "at 10 seconds A is ahead of B by 6 meters
\n" ); document.write( "---
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