document.write( "Question 68645: Please help me solve for I for this equation: \"+3I1-4I2=17+and+I1%2B3I2=-3+\".\r
\n" ); document.write( "\n" ); document.write( "Note the I1 (has a number 1 at the bottom right hand corner and the I2 has the number 2 on the right hand corner.)
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Algebra.Com's Answer #48923 by rmromero(383)\"\" \"About 
You can put this solution on YOUR website!
\"+3I%5B1%5D-4I%5B2%5D=17+and+I%5B1%5D%2B3I%5B2%5D=-3+\"
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\n" ); document.write( "Let us represent other variables.
\n" ); document.write( "\"x+=+I%5B1%5D\"
\n" ); document.write( "\"y+=+I%5B2%5D\"
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\n" ); document.write( "Rewrite the equations
\n" ); document.write( "3x-4y=17
\n" ); document.write( "x+3y=-3
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\n" ); document.write( "We can solve for the variables using elimination method.
\n" ); document.write( "Multiply -3 to x+3y=-3
\n" ); document.write( "3x - 4y = 17
\n" ); document.write( "-3x - 9y = 9
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\n" ); document.write( "Add the two equations
\n" ); document.write( "-13y = 26
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Divide -13 both sides
\n" ); document.write( "y = -2 <<<<<<<<<<<<<<<\"y+=+I%5B2%5D\"
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\n" ); document.write( "Substitute 2 for y in either equation. Solve for x.
\n" ); document.write( "x+3y=-3, y = 2
\n" ); document.write( "x + 3(-2)= -3
\n" ); document.write( "x - 6 = -3
\n" ); document.write( "x = 3 <<<<<<<<<<<<<< \"x+=+I%5B1%5D\"\r
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Checking: \r
\n" ); document.write( "\n" ); document.write( "3x-4y=17 , x = 3, y = -2
\n" ); document.write( "3(3) - 4(-2) = 17
\n" ); document.write( "9 + 8 = 17
\n" ); document.write( "17 = 17 ----------->> True
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\n" ); document.write( "x+3y=-3, x = 3, y = -2
\n" ); document.write( "3 + 3(-2) = -3
\n" ); document.write( "3 -6 = -3
\n" ); document.write( "-3 = -3 --------->> True\r
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