document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=812575>Question 812575</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve log(x+3)+log5=log 20 algebraically?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #489215 by </B><A HREF=/tutors/aboutme.mpl?userid=erica65404><B>erica65404(394)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=erica65404><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=erica65404><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=489215\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Log(x+3)+log5 is the same thing as log(5(x+3))<BR>\n" );
document.write( "log(5x+15)=log20<BR>\n" );
document.write( "both sides have logs with the same base so you can get rid off the logs<BR>\n" );
document.write( "5x+15=20<BR>\n" );
document.write( "5x=5<BR>\n" );
document.write( "x=1 </SPAN>\n" );
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