document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=811230>Question 811230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 16x squared minus y squared minus 128x plus 240 = 0<BR>\n" );
document.write( "It's a Hyperbola identify the center, vertices, and foci. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #489212 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=489212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 16x squared minus y squared minus 128x plus 240 = 0<BR>\n" );
document.write( "It's a Hyperbola identify the center, vertices, and foci.<BR>\n" );
document.write( "***<BR>\n" );
document.write( "Given hyperbola has a horizontal transverse axis<BR>\n" );
document.write( "Its standard form of equation: (x-h)^2-(y-k)^2=1, (h,k)=(x,y) coordinates of cente.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "16x^2-y^2-128x+240=0<BR>\n" );
document.write( "16x^2-128x-y^2=-240<BR>\n" );
document.write( "16(x^2-8x+16)-y^2=-240+256<BR>\n" );
document.write( "16(x-4)^2-y^2=16<BR>\n" );
document.write( "(x-4)^2/1-y^2/16=1<BR>\n" );
document.write( "Center:(4,0)<BR>\n" );
document.write( "a^2=1<BR>\n" );
document.write( "a=1<BR>\n" );
document.write( "b^2=16<BR>\n" );
document.write( "b=4<BR>\n" );
document.write( "c^2=a^2+b^2=1+16=17<BR>\n" );
document.write( "c=&#8730;17&#8776;4.12<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Vertices:(4±a,0)=(4±1,0)=(3,0) and (5,0)<BR>\n" );
document.write( "Foci:(4±c,0)=(4±4.12,0)=(-.12,0) and (8.12,0) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );