document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=812336>Question 812336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> SIN A =-2/7 AND A IS LIE ON QUADRANT III..<BR>\n" );
document.write( "WHAT IS THE VALUE OF TAN A??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #489196 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=489196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SIN A =-2/7 AND A IS LIE ON QUADRANT III..<BR>\n" );
document.write( "WHAT IS THE VALUE OF TAN A???<BR>\n" );
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document.write( "Note: In QIII, x is negative and y is negative<BR>\n" );
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document.write( "Since sin = y/r, y = -2 and r = 7<BR>\n" );
document.write( "So, x = -sqrt[7^2-2^2] = -sqrt(45) = -(3)sqrt(5)\r<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "tan = y/x<BR>\n" );
document.write( "So tan(A) = [-2]/[-(3)sqrt(5)] = (2/3)sqrt(5)/5 = (2/15)sqrt(5)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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