document.write( "Question 812501: I nee your help. How can the graph of g(x)=-(x-3)^2+12 be obtained from he graph of f(x)=x^2? \n" ); document.write( "

Algebra.Com's Answer #489178 by josgarithmetic(39617) $\"\"$ $\"About$

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Just a change in position from the reference graph of f(x). Up 12 units and to the right by 3 units. The function, g(x) is in standard form, h=3 and k=12. Standard Form for vertical parabola is $\"y=a%28x-h%29%5E2%2Bk\"$ .\r
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\n" ); document.write( "\n" ); document.write( "See carefully that while f(x) has a minimum point for vertex, now g(x) has a=-1, so now g(x) has its vertex as a MAXIMUM point, so parabola opens downward.\r
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\n" ); document.write( "\n" ); document.write( "f(x)=x^2 shown in green, and g(x) in red:
\n" ); document.write( " $\"graph%28400%2C400%2C-20%2C20%2C-20%2C20%2C-%28x-3%29%5E2%2B12%2Cx%5E2%29\"$ \n" ); document.write( "

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