document.write( "Question 1408: what the freak is the l.c.m AND the g.c.d. of 82, 96 and 112? i'm too tired to try this anymore!
\n" );
document.write( "Thanks! \n" );
document.write( "
Algebra.Com's Answer #489 by AnlytcPhil(1806)![]() ![]() You can put this solution on YOUR website! what the freak is the l.c.m AND the g.c.d. of 82, 96 and 112? i'm too tired to \n" ); document.write( "try this anymore! Thanks!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It's asking \"What is the smallest integer that 82,96 and 112 will divide into evenly?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Prime factor 82:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "82 = 2·41\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Prime factor 96\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "96 = 2·48 = 2·2·24 = 2·2·2·12 = 2·2·2·2·6 = 2·2·2·2·2·3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Prime factor 112\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "96 = 2·56 = 2·2·28 = 2·2·2·14 = 2·2·2·2·7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we have\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "82 = 2·41\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "96 = 2·2·2·2·2·3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "112 = 2·2·2·2·7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "82 contains 2 ONE time, 96 contains 2 FIVE times, 112 contains 2 FOUR times.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The largest of ONE, FIVE and FOUR is FIVE, so the LCM must contain 2 FIVE times.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "82 contains 41 ONE time, 96 contains 41 ZERO times, 112 contains 41 ZERO\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "times. The largest of ONE, ZERO and ZERO is ONE, so the LCM must contain 41\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ONE time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "96 contains 3 ONE time, 82 contains 3 ZERO times, 112 contains 3 ZERO times. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The largest of ONE, ZERO and ZERO is ONE, so the LCM must contain 3 ONE time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "112 contains 7 ONE time, 82 contains 7 ZERO times, 96 contains 7 ONE times. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The largest of ONE, ZERO and ZERO is ONE, so the LCM must contain 7 ONE time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the LCM is the integer that contains 2 FIVE times, 41 ONE time, 3 ONE time,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and 7 ONE time is 2·2·2·2·2·41·3·7 = 27552 \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "Edwin\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |