document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=811739>Question 811739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The first of three numbers exceeds the second by one less than the third.The sum of the second and third numbers is one more than the first.If the second is subtracted from the sum of the first and third numbers the result is 5.Determine the numbers.\r<BR>\n" );
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document.write( "let x,y,z the three numbers respectively\r<BR>\n" );
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document.write( "x-y=z-1     --> Eq. 1<BR>\n" );
document.write( "y+z=x+1     --> Eq. 2<BR>\n" );
document.write( "(x+z)-y=5   --> Eq. 3\r<BR>\n" );
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document.write( "Are my equations right? the answer is 4,2,3.I already got the third number which is 3 but I cant get the 4 and 2.Please help me!Thank you in advance! :D </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #488920 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=488920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-y=z-1,<BR>\n" );
document.write( "y+z=x+1,<BR>\n" );
document.write( "(x+z)-y=5 <BR>\n" );
document.write( "There is not enough info. <BR>\n" );
document.write( "y=x+2 is all we can deduce <BR>\n" );
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