document.write( "Question 811795: a truck drives north at 60 mph, one-and-half hour later a car drives in the the same direction at 70 mph . for how many hours must the car drive for it to be 50 miles ahead of the truck. \n" ); document.write( "
Algebra.Com's Answer #488904 by josmiceli(19441) You can put this solution on YOUR website! The truck's head start is \n" ); document.write( "Let \n" ); document.write( "it is \n" ); document.write( "Let \n" ); document.write( "when it meets the truck \n" ); document.write( "------------------------------ \n" ); document.write( "Equation for truck: \n" ); document.write( "(1) \n" ); document.write( "Equation for car: \n" ); document.write( "(2) \n" ); document.write( "------------ \n" ); document.write( "By substitution: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "------------ \n" ); document.write( "In 9 hrs they meet \n" ); document.write( "From the place where they meet, let \n" ); document.write( "the car go \n" ); document.write( "truck go \n" ); document.write( "Let \n" ); document.write( "truck's equation: \n" ); document.write( "(1) \n" ); document.write( "car's equation: \n" ); document.write( "(2) \n" ); document.write( "---------------- \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( "It takes 14 hrs for the car to get 50 mi ahead \n" ); document.write( "of the truck\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |