document.write( "Question 811795: a truck drives north at 60 mph, one-and-half hour later a car drives in the the same direction at 70 mph . for how many hours must the car drive for it to be 50 miles ahead of the truck. \n" ); document.write( "
Algebra.Com's Answer #488904 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The truck's head start is \"+60%2A1.5+=+90+\" mi
\n" ); document.write( "Let \"+t+\" = the driving time for the car when
\n" ); document.write( "it is \"+50+\" mi ahead of the truck
\n" ); document.write( "Let \"+d+\" = the distance the car travels
\n" ); document.write( "when it meets the truck
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\n" ); document.write( "Equation for truck:
\n" ); document.write( "(1) \"+d+-+90+=+60t+\"
\n" ); document.write( "Equation for car:
\n" ); document.write( "(2) \"+d+=+70t+\"
\n" ); document.write( "------------
\n" ); document.write( "By substitution:
\n" ); document.write( "(1) \"+70t+-+90+=+60t+\"
\n" ); document.write( "(1) \"+10t+=+90+\"
\n" ); document.write( "(1) \"+t+=+9+\"
\n" ); document.write( "------------
\n" ); document.write( "In 9 hrs they meet
\n" ); document.write( "From the place where they meet, let
\n" ); document.write( "the car go \"+d%5B2%5D+\" mi, and the
\n" ); document.write( "truck go \"+d%5B2%5D+-50+\"
\n" ); document.write( "Let \"+t%5B2%5D+\" = the time to do this
\n" ); document.write( "truck's equation:
\n" ); document.write( "(1) \"+d%5B2%5D+-+50+=+60t%5B2%5D+\"
\n" ); document.write( "car's equation:
\n" ); document.write( "(2) \"+d%5B2%5D+=+70t%5B2%5D+\"
\n" ); document.write( "----------------
\n" ); document.write( "(1) \"+70t%5B2%5D+-+50+=+60t%5B2%5D+\"
\n" ); document.write( "(1) \"+10t%5B2%5D+=+50+\"
\n" ); document.write( "(1) \"+t%5B2%5D+=+5+\"
\n" ); document.write( "\"+t+%2B+t%5B2%5D+=+9+%2B+5+\"
\n" ); document.write( "It takes 14 hrs for the car to get 50 mi ahead
\n" ); document.write( "of the truck\r
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