document.write( "Question 68693: state the slope and y-intercept of the graph of each equation.
\n" ); document.write( "3. y=2/3x
\n" ); document.write( "6. 3x-24+6=0\r
\n" ); document.write( "\n" ); document.write( "weite an equation in slope-intercept form for the line that satisfies each set of conditions.\r
\n" ); document.write( "\n" ); document.write( "12. slope 3, passes through (1,3)
\n" ); document.write( "15. slope 3, passes through (2,0)\r
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Algebra.Com's Answer #48888 by checkley71(8403)\"\" \"About 
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Y=2/3X HAS A SLOPE OF 2/3 & A Y INTERCEPT OF 0.
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\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+2x%2F3%29+\" (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 2x/3).
\n" ); document.write( "3X-24+6=0
\n" ); document.write( "3X=18
\n" ); document.write( "X=18/3
\n" ); document.write( "X=6 THIS SLOPE IS UNDEFINED AND DESCRIBES A VERTICLE LINE THROUGH X=6
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\n" ); document.write( "a slope of 3 & passing through (1,3) is
\n" ); document.write( "y=3x+b
\n" ); document.write( "3=3*1+b
\n" ); document.write( "3=3+b
\n" ); document.write( "b=3-3
\n" ); document.write( "b=0 thus the equation is
\n" ); document.write( "y=3x
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\n" ); document.write( "a slope of 3 passing theough (2,0)is
\n" ); document.write( "0=3*2+b
\n" ); document.write( "b=-6 thus the equation of this line is
\n" ); document.write( "y=3x-6
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