document.write( "Question 811699: How do you solve this by using the subsitution?\r
\n" ); document.write( "\n" ); document.write( "y = (2/3)x – 1
\n" ); document.write( "y = -x + 4\r
\n" ); document.write( "\n" ); document.write( "Show how you got your answer, so I can do the rest of these problem myself.
\n" ); document.write( "

Algebra.Com's Answer #488861 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
To solve a system by substitution, you start by finding an equation that is a formula to calculate one variable from the other. It would start with
\n" ); document.write( "\"y\"\"%22=...%22\"
\n" ); document.write( "or \"x\"\"%22=...%22\"
\n" ); document.write( "If there is no equation like that, you \"make\" one by solving for \"y\" or \"x\" in one of the equations.
\n" ); document.write( "
\n" ); document.write( "Your system has an equation like that. (In fact, it has two of those).
\n" ); document.write( "If \"y+=+%282%2F3%29x+-+1\" , you can substitute the expression \"%282%2F3%29x+-+1\" for \"y\" in the other equation to get
\n" ); document.write( "\"%282%2F3%29x+-+1=+-x%2B4\"
\n" ); document.write( "Now, you just solve for \"x\" , to start.
\n" ); document.write( "Adding \"x\" to both sides, you get
\n" ); document.write( "\"x%2B%282%2F3%29x+-+1=x-x%2B4\"
\n" ); document.write( "\"x%2B%282%2F3%29x+-+1=4\"
\n" ); document.write( "Adding \"1\" to both sides, you get
\n" ); document.write( "\"x%2B%282%2F3%29x+-+1=4\"
\n" ); document.write( "\"x%2B%282%2F3%29x+-+1%2B1=4%2B1\"
\n" ); document.write( "\"x%2B%282%2F3%29x=5\"
\n" ); document.write( "\"%281%2B2%2F3%29x=5\"
\n" ); document.write( "\"%285%2F3%29x=5\"
\n" ); document.write( "Now, multiplying both sides times \"3%2F5\" ,
\n" ); document.write( "or dividing both sides by \"5%2F3\" (same thing), you find that
\n" ); document.write( "\"%283%2F5%29%285%2F3%29x=5%283%2F5%29\"
\n" ); document.write( "\"x=5%283%2F5%29\"
\n" ); document.write( "\"highlight%28x=3%29\"
\n" ); document.write( "Now you go back to the equation that had \"y\"\"%22=...%22\" (any of the two) and use it to calculate \"y\" from the \"x=3\" you just found.
\n" ); document.write( "Substituting \"3\" for \"x\" in \"y=-x%2B4\" you find
\n" ); document.write( "\"y=-3%2B4\"
\n" ); document.write( "\"highlight%28y=1%29\"
\n" ); document.write( "
\n" );