document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=811685>Question 811685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simplify the compound fraction and show work:\r<BR>\n" );
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document.write( "1/(x+1) +1/2<BR>\n" );
document.write( "     over<BR>\n" );
document.write( "3/(2x^2 +4x +2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #488853 by </B><A HREF=/tutors/aboutme.mpl?userid=brysca><B>brysca(112)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=brysca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=brysca><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=488853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I gave it a shot. It looks right and I'm pretty sure it's right but I'm sorry if it's not.\r<BR>\n" );
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document.write( "First, combine the 1 and the .5 in the denominator<BR>\n" );
document.write( "x+1+.5<BR>\n" );
document.write( "=x+1.5\r<BR>\n" );
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document.write( "So the question translates to this:<BR>\n" );
document.write( "1/(x+1.5) divided by 3/(2x^2 +4x +2)\r<BR>\n" );
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document.write( "So whenever you divide by a fraction, you multiply by its inverse instead so it looks like this:<BR>\n" );
document.write( "1/(x+1.5) * (2x^2 +4x +2)/3\r<BR>\n" );
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document.write( "(2x^2 +4x +2) simplifies to (x+1)(2x+2) so you rewrite it like this<BR>\n" );
document.write( "1/(x+1.5) * (x+1)(2x+2)/3\r<BR>\n" );
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document.write( "You should get something like this when multiplied:<BR>\n" );
document.write( "(x+1)(2x+2)/(3x+4.5) </SPAN>\n" );
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