document.write( "Question 68688: solve each system by substitution
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document.write( "5x - 2y = -5
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document.write( " y- 5x = 3\r
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document.write( "4x - 12y = 5
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document.write( "-x + 3y -1 \n" );
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Algebra.Com's Answer #48880 by rmromero(383)![]() ![]() ![]() You can put this solution on YOUR website! 5x - 2y = -5 \n" ); document.write( " y- 5x = 3\r \n" ); document.write( "\n" ); document.write( "Here are the Steps using Substition method \n" ); document.write( "1. In either equation, solve for one variable in terms of the other. Since y- 5x = 3 is simplier than the other eqution, we will solve x in terms of y. \n" ); document.write( "y- 5x = 3 \n" ); document.write( "y = 5x + 3 \n" ); document.write( " \n" ); document.write( "2. Substitute for that variable in the other equation. Solve. \n" ); document.write( "5x - 2y = -5 , y = 5x + 3 \n" ); document.write( "5x - 2(5x+3) = -5 \n" ); document.write( "5x -10x - 6 = -5 \n" ); document.write( "-5x = 1 \n" ); document.write( "x = -1/5 \n" ); document.write( " \n" ); document.write( "3. Substitute the result from step 2 in either equation. Solve for the other variable. \n" ); document.write( " y- 5x = 3, x = -1/5 \n" ); document.write( "y - 5(-1/5) = 3 \n" ); document.write( "y + 1 = 3 \n" ); document.write( "y = 2 \n" ); document.write( " \n" ); document.write( "4. Check the solution in both original equations. \n" ); document.write( "5x - 2y = -5, x = 2 and y = -1/5 \n" ); document.write( "5(-1/5) - 2(2) = -5 \n" ); document.write( "-1 - 4 = -5 \n" ); document.write( "-5 = -5 ----------->> True\r \n" ); document.write( "\n" ); document.write( "y- 5x = 3 \n" ); document.write( "2 - 5(-1/5) = 3 \n" ); document.write( "2 + 1 = 3 \n" ); document.write( "3 = 3 ----------->> True \n" ); document.write( " \n" ); document.write( "Therefore the solution of the systems of equation is x = -1/5 and y = 2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "4x - 12y = 5 \n" ); document.write( "-x + 3y -1 <<<<<=== im not sure what do you mean by this. please encode it clearly.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |