document.write( "Question 68680: If the area of this rectangle is 105cm2 then the length is ____cm, the width is ____ cm, and the perimeter is ____cm. The width of the rectangle is (x) and the length is (2x+1). This is all the information the problem gives me. The problem was given to me on a study guide along with the answer key. The length is 15cm, and the width is 7 but I dont understand how they came about this answer. Can you please help me?? \n" ); document.write( "
Algebra.Com's Answer #48877 by Earlsdon(6294)\"\" \"About 
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Starting with the formula for the area of a rectangle: \"A+=+L%2AW\" which is given as 105 sq.cm., you can substitute x for W and (2x+1) for L to get:
\n" ); document.write( "\"%282x%2B1%29%28x%29+=+105\" Simplify and solve for x.
\n" ); document.write( "\"2x%5E2%2Bx+=+105\" Subtract 105 from both sides of the equation.
\n" ); document.write( "\"2x%5E2%2Bx-105+=+0\" Factor this quadratic equation.
\n" ); document.write( "\"%282x%2B15%29%28x-7%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"2x%2B15+=+0\" and/or\"x-7+=+0\" from which you get:
\n" ); document.write( "\"2x%2B15+=+0\" Subtract 15 from both sides.
\n" ); document.write( "\"2x+=+-15\"} Divide both sides by 2.
\n" ); document.write( "\"x+=+-%287.5%29\" Discard this negative solution as the width must be a positive value.
\n" ); document.write( "\"x-7+=+0\"
\n" ); document.write( "\"x+=+7\"
\n" ); document.write( "The width is 7 cm.
\n" ); document.write( "The length is 2x+1 = 2(7)+1 = 15 cm.
\n" ); document.write( "The perimeter is:
\n" ); document.write( "\"P+=+2L+%2B+2W\"
\n" ); document.write( "\"P+=+2%2815%29%2B2%287%29\"
\n" ); document.write( "\"P+=+30%2B14\"
\n" ); document.write( "\"P+=+44\" cm.
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