document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=811480>Question 811480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve simplify this radical:<BR>\n" );
document.write( "27^-2/3 / 27^-1/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #488767 by </B><A HREF=/tutors/aboutme.mpl?userid=Simeonkay><B>Simeonkay(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Simeonkay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Simeonkay><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=488767\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (27^-2/3)/(27^-1/3)<BR>\n" );
document.write( "since it have the same base as 27, apply the law of logarithm,i.e<BR>\n" );
document.write( "27^-2/3 + 1/3, simplify the fraction of the power<BR>\n" );
document.write( "27^-1/3<BR>\n" );
document.write( "find the inverse cube root of 27, which is 3^-1, which can be written as 1/3.<BR>\n" );
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