document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=811484>Question 811484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i cant find the solution can someone help me how to do this step by step <BR>\n" );
document.write( "consider the line y=3/2x-4\r<BR>\n" );
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document.write( "Find the equation of the line that is parallel to this line and passes through the point (3,6)?\r<BR>\n" );
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document.write( "Find the equation of the line that is perpendicular to this line and passes through the point (3,6)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #488766 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=488766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> given y = 3x/2 -4<BR>\n" );
document.write( "1)  parallel lines have the same slope, therefore a line parallel to the given line and passes through the point (3,6) is<BR>\n" );
document.write( "6 = (3/2)*3 +c<BR>\n" );
document.write( "12/2 = 9/2 +c<BR>\n" );
document.write( "c = 3/2<BR>\n" );
document.write( "y = 3x/2 +3/2<BR>\n" );
document.write( "here is the graph of the parallel lines<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+3x%2F2+-4%2C+3x%2F2+%2B3%2F2%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+3x%2F2+-4%2C+3x%2F2+%2B3%2F2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "2) the product of the slopes of two perpendicular lines is negative one, therefore<BR>\n" );
document.write( "3/2 * m = -1 and m is -2/3, consider that this new line passes through point (3,6)<BR>\n" );
document.write( "6 = (-2/3)*3 +c<BR>\n" );
document.write( "c = 8<BR>\n" );
document.write( "y = -2x/3 +8<BR>\n" );
document.write( "here is the graph of the perpendicular lines<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+3x%2F2+-4%2C+-2x%2F3+%2B8%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+3x%2F2+-4%2C+-2x%2F3+%2B8%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );