document.write( "Question 811419: The area of a rectangular conference room is represented by the equation A = (x2 + 17x + 72) feet2.\r
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document.write( "If x = 6 feet and the width = (x + 8) feet, what is the perimeter, in feet, of the room?
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Algebra.Com's Answer #488735 by Stitch(470)![]() ![]() ![]() You can put this solution on YOUR website! The equation for the area of a rectancle is A = L * W. \n" ); document.write( "The equation for the perimeter of a rectangle is P = 2L + 2W. \n" ); document.write( "-------------------- \n" ); document.write( "Given: X = 6 \n" ); document.write( "Given: \n" ); document.write( "Given: \n" ); document.write( "-------------------- \n" ); document.write( "Since we know that X = 6, we can solve for W. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------- \n" ); document.write( "Now we can solve for the area by plugging 6 into the equation for X. \n" ); document.write( "Given: \n" ); document.write( " \n" ); document.write( "Simplify \n" ); document.write( " \n" ); document.write( "Combine like terms. \n" ); document.write( " \n" ); document.write( "------------------- \n" ); document.write( "Now we can solve for the length. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Divide both sides by 14. \n" ); document.write( " \n" ); document.write( "-------------------- \n" ); document.write( "Now we can use the perimeter equation. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Simplify \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The perimeter of the room is 58 feet. \n" ); document.write( " |