document.write( "Question 811332: a shop keeper sells two phones for rs 6000, one at a gain of 25 percent and the other at a loss of 25 percent. find the overall gain or loss percent.
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Algebra.Com's Answer #488698 by Edwin McCravy(20060)\"\" \"About 
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a shop keeper sells two phones for rs 6000, one at a gain of 25 percent and the other at a loss of 25 percent. find the overall gain or loss percent.
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document.write( "That is not enough information.\r\n" );
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document.write( "If the first phone sold for rs 1000 and the second phone at rs 5000, then\r\n" );
document.write( "1. The gain of 25 percent of the first phone is (1000)(0.25) = rs 250.\r\n" );
document.write( "2. The loss of 25 percent of the second phone is (5000)(-0.25) = rs - rs 1250.\r\n" );
document.write( "3. That would be a total LOSS of rs 250 - rs 1250 = -rs 1000 a LOSS of rs 1250.\r\n" );
document.write( "4.  That would be a total LOSS of 1250/6000 = 20.8 percent.\r\n" );
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document.write( "If the first phone sold for rs 2000 and the second phone at rs 4000, then\r\n" );
document.write( "1. The gain of 25 percent of the first phone is (2000)(0.25) = rs 500.\r\n" );
document.write( "2. The loss of 25 percent of the second phone is (4000)(-0.25) = - rs 1000.\r\n" );
document.write( "3. That would be a total LOSS of rs 500 - rs 1000 = -rs 500 a LOSS of rs 500.\r\n" );
document.write( "4.  That would be a total LOSS of 500/6000 = 8.3 percent.\r\n" );
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document.write( "If the first phone sold for rs 4000 and the second phone at rs 2000, then\r\n" );
document.write( "1. The gain of 25 percent of the first phone is (4000)(0.25) = rs 1000.\r\n" );
document.write( "2. The loss of 25 percent of the second phone is (2000)(-0.25) = - rs 500.\r\n" );
document.write( "3. That would be a total GAIN of rs 1000- rs 500 = -rs 500 a GAIN of rs 500.\r\n" );
document.write( "4.  That would be a total GAIN of 500/6000 = 8.3 percent.\r\n" );
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document.write( "If the first phone sold for rs 5000 and the second phone at rs 1000, then\r\n" );
document.write( "1. The gain of 25 percent of the first phone is (5000)(0.25) = rs 1250.\r\n" );
document.write( "2. The loss of 25 percent of the second phone is (1000)(-0.25) = rs 1250.\r\n" );
document.write( "3. That would be a total GAIN of rs 1250 - rs 250 = rs 1000 a GAIN of rs 1250.\r\n" );
document.write( "4.  That would be a total GAIN of 1250/6000 = 20.8 percent.\r\n" );
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document.write( "We need more information.\r\n" );
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document.write( "Edwin

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