document.write( "Question 811304: A man is 20 yrs old. his daughter is 5. in how many years will the man's age twice his daughter's age \n" ); document.write( "
Algebra.Com's Answer #488695 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+20+%2B+x+\" = the man's age \"+x+\" years from now
\n" ); document.write( "Let \"+5+%2B+x+\" = the daughter's age \"+x+\" years from now
\n" ); document.write( "------------
\n" ); document.write( "\"+20+%2B+x+=+2%2A%28+5+%2B+x+%29+\"
\n" ); document.write( "\"+20+%2B+x+=+10+%2B+2x+\"
\n" ); document.write( "\"+x+=+10+\"
\n" ); document.write( "--------------
\n" ); document.write( "In 10 years the man's age is twice the daughter's age
\n" ); document.write( "--------------
\n" ); document.write( "check:
\n" ); document.write( "\"+20+%2B+x+=+2%2A%28+5+%2B+x+%29+\"
\n" ); document.write( "\"+20+%2B+10+=+2%2A%28+5+%2B+10+%29+\"
\n" ); document.write( "\"+30+=+2%2A15+\"
\n" ); document.write( "\"+30+=+30+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );