document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=811313>Question 811313</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5 men can complete a job in 4 days.In how many days can 10 men working at 1/4 of the previous rate complete the job. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #488694 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=488694\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5 men can complete a job in 4 days<BR>\n" );
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document.write( "Twice as many men can do the same <BR>\n" );
document.write( "job in half the time, so<BR>\n" );
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document.write( "10 men can do the job in 2 days<BR>\n" );
document.write( "working at the same rate<BR>\n" );
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document.write( "Working at 1/4 of that rate, the<BR>\n" );
document.write( "10 men take 4 times as long, so<BR>\n" );
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document.write( "10 men do the job in 8 days<BR>\n" );
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