document.write( "Question 811275: The perimiter of a rectangular field is 228 yards. If the width of the field is 52 yards, what is the length? \n" ); document.write( "

Algebra.Com's Answer #488674 by TimothyLamb(4379) $\"\"$ $\"About$

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2L + 2W = 228
\n" ); document.write( "W = 52
\n" ); document.write( "---
\n" ); document.write( "2L + 2W = 228
\n" ); document.write( "2L + 2(52) = 228
\n" ); document.write( "2L + 104 = 228
\n" ); document.write( "2L = 124
\n" ); document.write( "---
\n" ); document.write( "L = 62
\n" ); document.write( "---
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