document.write( "Question 811261: Diana has two different solutions of acid 10% and 40%. How much of the 40% and 10% solutions should she mix to make 15 liters of 25% solution?
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Algebra.Com's Answer #488666 by josgarithmetic(39629)\"\" \"About 
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Hundreds of these examples are all the same general problem.\r
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\n" ); document.write( "\n" ); document.write( "H = percent concentration of the higher strength material
\n" ); document.write( "T = target percent concentration
\n" ); document.write( "L = percent concentration of the lower strength material
\n" ); document.write( "M = size of resulting mixture
\n" ); document.write( "u = amount of the L strength material to use
\n" ); document.write( "v = amount of the H strength material to use\r
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\n" ); document.write( "\n" ); document.write( "Your given description makes these assignments:
\n" ); document.write( "H = 40 %
\n" ); document.write( "T = 25%
\n" ); document.write( "L = 10 %
\n" ); document.write( "M = 15 liters
\n" ); document.write( "u and v are unknown, liters.\r
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\n" ); document.write( "\n" ); document.write( "System of equations is:
\n" ); document.write( "\"%28Lu%2BHv%29%2FM=T\" and \"u%2Bv=15\"
\n" ); document.write( "Solve for u and v, both which are linear, so you will have two linear equations in u and v.
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