document.write( "Question 68657: It says use substitution to solve each system of equation
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Algebra.Com's Answer #48856 by rmromero(383) $\"\"$ $\"About$

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Here are the Steps in solving systems of equation using Substition method\r\n" );
document.write( "1. In either equation, solve for one variable in terms of the other.Using 2x+y=104, solve y in terms of x.\r\n" );
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2x+y=104\r\n" );
document.write( "y = -2x + 104\r\n" );
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document.write( "2. Substitute -2x + 104 for y in the other equation 0.5x-2y=17. Solve x.\r\n" );
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0.5x-2(-2x+104)=17 \r\n" );
document.write( "Apply distributive property to simplify the equation\r\n" );
document.write( "0.5x - 2(-2x) - 2(104) = 17\r\n" );
document.write( "0.5x + 4x - 208 = 17\r\n" );
document.write( "4.5x - 208 = 17\r\n" );
document.write( "4.5x = -225 \r\n" );
document.write( "Divide both sides by 4.5 to solve for x\r\n" );
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document.write( "3. Substitute the result from step 2 in either equation. Solve for the other variable y.\r\n" );
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 2x+y=104 , x = 50\r\n" );
document.write( "2(50) + y = 104\r\n" );
document.write( "100 + y = 104\r\n" );
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document.write( "4. Check the solution in both original equations.\r\n" );
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2x+y=104 when x=50 and y=4\r\n" );
document.write( "2(50) + 4 = 104\r\n" );
document.write( "100 + 4 = 104\r\n" );
document.write( "104 = 104 ----------->> True\r\n" );
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document.write( "0.5x-2y=17  when x=50 and y=4\r\n" );
document.write( "0.5(50)-2(4)= 17  \r\n" );
document.write( "25 - 8 = 17\r\n" );
document.write( "17 = 17 --------->> True\r\n" );
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Therefore the solution of the systems of equation is x = 50 and y = 4\r\n" );
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