document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=810908>Question 810908</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle is inscribed in the square. If the area of the circle is 16&#960;  square centimeters, find the length of one of the diagonals of the square.<BR>\n" );
document.write( "A=pi x r squared divided by 2<BR>\n" );
document.write( "I got 25.12 which was incorrect.  What am I doing wrong? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #488541 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=488541\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=pi*r^2<BR>\n" );
document.write( "why divided by 2??\r<BR>\n" );
document.write( "\n" );
document.write( "r=4<BR>\n" );
document.write( "2r=diameter and one side of square<BR>\n" );
document.write( "diameter =8<BR>\n" );
document.write( "one side = 8 <BR>\n" );
document.write( "2*8^2=128<BR>\n" );
document.write( "sqrt(128)=diagonal<BR>\n" );
document.write( "11.3 is the diagonal </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );