document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=810824>Question 810824</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A total of $16,000 is invested in 3 accounts earning 4%, 6%, and 8% annual interest.  The combined interest for one year is $934.  If the amount invested at 8% is three times the amount at 6%, find the amount invested at 4%.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #488514 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=488514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> investment @ 6%----------x<BR>\n" );
document.write( "investment at 8%---------3x\r<BR>\n" );
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document.write( "investment @%4 ----------16000-(3x+x)=16000-4x\r<BR>\n" );
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document.write( "6%x+8%3x+4%(16000-4x)=934\r<BR>\n" );
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document.write( "multiply equation by 100\r<BR>\n" );
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document.write( "6x+8*3x+4(16000-4x)=93400\r<BR>\n" );
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document.write( "6x+24x+64000-16x=93400\r<BR>\n" );
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document.write( "14x=93400-64000\r<BR>\n" );
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document.write( "14x=429400<BR>\n" );
document.write( "x=29400/14<BR>\n" );
document.write( "x=2100 \r<BR>\n" );
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document.write( "Investment 4% = 16000-4x<BR>\n" );
document.write( "=16000-4*2100<BR>\n" );
document.write( "=16000-8400<BR>\n" );
document.write( "=7600 </SPAN>\n" );
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