document.write( "Question 810798: In 4 hours, Kerrie can go 15 miles upriver and come back. the speed of the current is 5 mph. what is the speed of the boat in still water?
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Algebra.Com's Answer #488498 by josgarithmetic(39630)\"\" \"About 
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Direction_________speed____________time_________________distance
\n" ); document.write( "upriver___________r-5______________(___)________________15
\n" ); document.write( "downriver_________r+5______________(___)________________15
\n" ); document.write( "Total________________________________4\r
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\n" ); document.write( "\n" ); document.write( "The way Rate*Time=Distance works, know that Time=Distance/Rate:\r
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\n" ); document.write( "\n" ); document.write( "Direction_________speed____________time_________________distance
\n" ); document.write( "upriver___________r-5______________\"15%2F%28r-5%29\"________________15
\n" ); document.write( "downriver_________r+5______________\"15%2F%28r%2B5%29\"________________15
\n" ); document.write( "Total________________________________4\r
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\n" ); document.write( "\n" ); document.write( "Solve for r in \"highlight%2815%281%2F%28r-5%29%2B1%2F%28r%2B5%29%29=4%29\"
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