document.write( "Question 810816: A coach said to his assistant, \"Today I saw three of our biggest fans. The product of their ages is 2450. Can you tell me what their ages were? \n" ); document.write( "
Algebra.Com's Answer #488473 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let's get all the prime factors of 2450\r\n" );
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document.write( "2450 = 2×5×5×7×7\r\n" );
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document.write( "We need to make three groups from these prime factors.  The factor 1\r\n" );
document.write( "won't help us because 1-year old babies aren't fans.\r\n" );
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document.write( "The oldest the youngest could be is 7 years old. For if the youngest \r\n" );
document.write( "were the next possible age, 2×5 = 10 years, the product of the other\r\n" );
document.write( "two ages would have to be 5×7×7, and any way you group those factors,\r\n" );
document.write( "one of the others would have to be 7 or 5, both younger than 10.\r\n" );
document.write( "So there is no doubt that the oldest age the youngest can be is 7.\r\n" );
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document.write( "The other two could be another 7 year-old and a \r\n" );
document.write( "2×5×5 = 50-year old.\r\n" );
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document.write( "1.  That's one way, ages 7, 7 and 50 because 7×7×50 = 2450\r\n" );
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document.write( "The other two could be a 2×5 = 10-year-old, and a 5×7 = 35 year old:\r\n" );
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document.write( "2.  That's a second way, ages 7, 10, and 35, because 7×10×35 = 2450.\r\n" );
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document.write( "Or the other two could be 2×7 - 14-year-old. and a 5×5 = 25 year-old.\r\n" );
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document.write( "3.  That's a third way, ages 7, 14, and 25, because 7×14×25 = 2450\r\n" );
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document.write( "Those three are tho only ways, unless you would allow 1-year-old babies,\r\n" );
document.write( "2-year old toddlers, or 5-year old kindergarteners.  I think they'd all\r\n" );
document.write( "have to be at least in elementary school to be a fan, don't you think?  \r\n" );
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document.write( "Edwin
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