document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68615>Question 68615</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x - 3y = 12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48842 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IF THIS IS THE FORMULA FOR PLOTTING A LINE THEN<BR>\n" );
document.write( "2X-3Y=12<BR>\n" );
document.write( "-3Y=-2X+12<BR>\n" );
document.write( "Y=-2X/-3+12/-3<BR>\n" );
document.write( "Y=2X/3-4<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+10%2C+-10%2C+10%2C+y+=+2x%2F3+-4%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+10%2C+-10%2C+10%2C+y+=+2x%2F3+-4%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x200 pixels, x rom -6 to 10, y from -10 to 10, y = 2x/3 -4).  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );