document.write( "Question 810786: Find cos(2 theta)
\n" ); document.write( "Given : tan theta = 12/5, theta is in quadrant 3
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Algebra.Com's Answer #488410 by stanbon(75887)\"\" \"About 
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Find cos(2 theta)
\n" ); document.write( "Given : tan theta = 12/5, theta is in quadrant 3
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\n" ); document.write( "Note: Both x and y are negative in QIII
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\n" ); document.write( "Since tan = y/x = 12/5, y = -12 and x = -5
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\n" ); document.write( "Then r = sqrt[12^2+5^2] = sqrt[169] = 13
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\n" ); document.write( "cos = x/r = -5/13
\n" ); document.write( "sin = y/4 = -12/13
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\n" ); document.write( "Your Problem::
\n" ); document.write( "cos(2 t) = cos^2(t)-sin^2(t) = (5/13)^2 - (12/13)^2 = (25-144)/169 = -119/169
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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