document.write( "Question 810786: Find cos(2 theta)
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document.write( "Given : tan theta = 12/5, theta is in quadrant 3 \n" );
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Algebra.Com's Answer #488410 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find cos(2 theta) \n" ); document.write( "Given : tan theta = 12/5, theta is in quadrant 3 \n" ); document.write( "-------- \n" ); document.write( "Note: Both x and y are negative in QIII \n" ); document.write( "---- \n" ); document.write( "Since tan = y/x = 12/5, y = -12 and x = -5 \n" ); document.write( "------------ \n" ); document.write( "Then r = sqrt[12^2+5^2] = sqrt[169] = 13 \n" ); document.write( "------------------------ \n" ); document.write( "cos = x/r = -5/13 \n" ); document.write( "sin = y/4 = -12/13 \n" ); document.write( "----- \n" ); document.write( "Your Problem:: \n" ); document.write( "cos(2 t) = cos^2(t)-sin^2(t) = (5/13)^2 - (12/13)^2 = (25-144)/169 = -119/169 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |