document.write( "Question 68619: 100 (x-3) = 450-50x \n" ); document.write( "
Algebra.Com's Answer #48839 by checkley71(8403)\"\" \"About 
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100(X-3)=450-50X
\n" ); document.write( "100X-300=450-50X
\n" ); document.write( "100X+50X=450+300
\n" ); document.write( "150X=750
\n" ); document.write( "X=750/150
\n" ); document.write( "X=5
\n" ); document.write( "PROOF
\n" ); document.write( "100(5-3)=450-50*5
\n" ); document.write( "100*2=450-250
\n" ); document.write( "200=200
\n" ); document.write( "
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