document.write( "Question 68619: 100 (x-3) = 450-50x \n" ); document.write( "
Algebra.Com's Answer #48839 by checkley71(8403) ![]() You can put this solution on YOUR website! 100(X-3)=450-50X \n" ); document.write( "100X-300=450-50X \n" ); document.write( "100X+50X=450+300 \n" ); document.write( "150X=750 \n" ); document.write( "X=750/150 \n" ); document.write( "X=5 \n" ); document.write( "PROOF \n" ); document.write( "100(5-3)=450-50*5 \n" ); document.write( "100*2=450-250 \n" ); document.write( "200=200 \n" ); document.write( " \n" ); document.write( " |