document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=810685>Question 810685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem is to evaluate the following without using a calculator: <BR>\n" );
document.write( "log9(3)-log9(4)+log9(12) <BR>\n" );
document.write( "So far I have used the laws of logarithms and gotten to the following point:<BR>\n" );
document.write( "log9(3/4x12)=y<BR>\n" );
document.write( "log9(3/48)=y<BR>\n" );
document.write( "log9(1/16)=y<BR>\n" );
document.write( "9^y=(1/16)\r<BR>\n" );
document.write( "\n" );
document.write( "Am I correct so far and how do I finish the problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #488353 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=488353\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You solved log9(3) - (log9(4) + log9(12)).<P><BR>\n" );
document.write( "The problem is log9(3)-log9(4)+log9(12) so it becomes log9(3*12/4) = log9(9) = 1<P><BR>\n" );
document.write( "The log9(12) is added, so multiply 3*12, then divide by 4. </SPAN>\n" );
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