document.write( "Question 68602: Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x-5y=4 and passing through (-3, 5).\r
\n" ); document.write( "\n" ); document.write( "I have done this every way that I can think of and can not come up with it being perpendicular. I can only come up with it as a parallel.\r
\n" ); document.write( "\n" ); document.write( "I have:
\n" ); document.write( "x-5y=4
\n" ); document.write( "x-5y-x=4-x
\n" ); document.write( "-5y=-x+4
\n" ); document.write( "-5y/(-5)=-x/(-5)+4/(-5)
\n" ); document.write( "y=1/5x-4/5\r
\n" ); document.write( "\n" ); document.write( "y-y[sub 1]=m(x-x[sub 1])
\n" ); document.write( "y-5=1/5(x-(-3))
\n" ); document.write( "y-5=1/5x+3/5
\n" ); document.write( "y-5+5 = 1/5x + 3/5 + 5
\n" ); document.write( "y = 1/5x + 28/5\r
\n" ); document.write( "\n" ); document.write( "Both slopes are 1/5 which makes it parallel. Am I doing something wrong here?
\n" ); document.write( "Thank you, Rich \n" ); document.write( "

Algebra.Com's Answer #48835 by rkennedy(3) $\"\"$ $\"About$

You can put this solution on YOUR website!
Okay I forgot one thing. I figured it out. To find the perpendicular you have to flip the slope and change the sign. It would be a slope of -5/1 or -5
\n" ); document.write( "Then it would be y - 5 = -5 (x - (-3))
\n" ); document.write( "y - 5 = -5 (x + 3)
\n" ); document.write( "y - 5 = -5x -15
\n" ); document.write( "y - 5 + 5 = -5x - 15 + 5
\n" ); document.write( "y = -5x - 10 \n" ); document.write( "

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